16x^2+60x-163=0

Solution for 16x^2+60x-163=0 equation:

16x^2+60x-163=0

a = 16; b = 60; c = -163;
Δ = b2-4ac
Δ = 602-4·16·(-163)
Δ = 14032
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{14032}=\sqrt{16*877}=\sqrt{16}*\sqrt{877}=4\sqrt{877}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{877}}{2*16}=\frac{-60-4\sqrt{877}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{877}}{2*16}=\frac{-60+4\sqrt{877}}{32}
$